WEBVTT

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The manuscript suggests designing observations for a purpose as further work.

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This extension gives a small, explicitly stipulated example.

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We will not claim a new algorithm, complexity classification or real-world

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cost model from this four-state calculation.

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Our original cards use X for dot and Y for stripe: A

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has only a dot, B both, C only a stripe, and D

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neither.

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Their two-bit annotations follow X,Y order.

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A selected signature lists answers to the chosen test slots.

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Positive combinations of test regions generate the opens.

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Choosing a test makes it available; it does not assert its answer.

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Two states are distinguished here when those selected signatures differ.

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One goal is to distinguish designated valuations by different signatures.

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Another is to make a target subset open so membership can be

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certified.

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These goals need not select the same tests, even on the same

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carrier.

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Allow only three candidate tests: X, Y and their conjunction.

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Assign acquisition costs one, three and two respectively.

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These invented planning costs are separate from the coordinate weights used in

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the distance lectures.

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With three candidates there are only eight menus to inspect.

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Exhaustive enumeration solves this tiny example.

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It does not prove that a particular procedure scales well or is

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optimal for a general observation-design problem.

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X differs at A and D, while Y is false at both

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and the conjunction is false at both.

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The single X test therefore distinguishes the pair.

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Its cost is one, the least positive cost in the declared library.

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Selecting that test changes the menu.

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It does not assert that X is true and does not remove

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D.

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The design objective concerns potential distinctions supported by the interface, not a

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premise update already performed.

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Now seek a menu making the singleton B certifiable.

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X alone cannot do this because its true region also contains A.

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Y alone also includes C.

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Distinguishing one designated pair was therefore not the same design task.

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The conjunction's truth region is exactly B.

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Selecting it alone makes B open at cost two.

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Selecting X and Y separately also generates B through intersection, but their

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total acquisition cost in our toy library is four.

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For a signature map, injective means that different input states always give

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different output signatures.

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To distinguish every valuation, the signature map must be injective.

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X and Y together achieve this at total cost four.

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The conjunction alone has only true and false signatures and cannot separate

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three of the false valuations.

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The other two-test menus still merge a pair.

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X with the conjunction cannot distinguish C from D.

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Y with the conjunction cannot distinguish A from D.

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Thus, within our declared library, X and Y is the least-cost

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menu giving full separation.

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Adding the conjunction raises cost without adding a needed distinction.

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In the stipulated library, compare the cheapest way to make B alone

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open with the cheapest way to distinguish every valuation.

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Why is the cheaper event-certification menu insufficient for the stronger separation

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goal?

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The conjunction alone certifies B for cost two, but A, C and

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D share its false signature.

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X and Y together cost four and distinguish all points.

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The optimal answer depends on the objective and the allowed test library.

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A useful design problem states exactly what must be distinguished or certified,

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which formulas may be selected and which costs are being minimized.

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An exhaustive toy example illustrates that formulation; it does not establish the

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further algorithmic or complexity results proposed by the manuscript.
