WEBVTT

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Interior asks whether the whole smallest open neighborhood fits inside an event.

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Closure asks whether that neighborhood meets the event at all.

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We are using the original four-state carrier and only positive X

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and Y.

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The fixed X,Y values are A: one-zero, B: one-one,

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C: zero-one and D: zero-zero.

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Our first event is classical X implies Y.

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One means true and zero means false.

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The topological boundary is the closure of an event with its interior

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removed.

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It can be understood as observational ambiguity: neighborhoods cannot settle membership wholly

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inside or wholly outside.

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It is not defined by the edge of a shaded shape on

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the screen.

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Retain the implication calculation from Lecture 18.

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Its interior is B and C and its closure is the whole

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carrier.

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Removing the interior from the closure leaves A and D as the

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boundary.

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A is outside the implication truth region.

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Its smallest neighborhood contains A outside and B inside.

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It cannot settle the event in either direction, so a boundary point

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need not satisfy the event.

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D satisfies implication, yet its neighborhood contains both satisfying and falsifying valuations.

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It also lies on the boundary.

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Truth at the centre and ambiguity of its available neighborhood are different

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properties.

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For the next event, XOR means exactly one of X and Y

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is true.

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The carrier and the positive observation menu stay fixed.

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The XOR truth region contains A and C.

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Under positive X and Y, A's and C's smallest neighborhoods

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both include B, which is outside this event.

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No nonempty open set fits inside XOR.

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The interior is empty.

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A, C and D have neighborhoods meeting XOR, while B's singleton

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neighborhood does not.

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The closure, and hence the boundary in this case, is A, C

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and D.

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Make both signs of X and Y available on the same carrier.

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Each complete minterm now certifies a singleton, so the topology is discrete.

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The truth table of XOR has not changed; A and C remain

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its true points.

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In a discrete topology every subset is both open and closed.

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XOR's interior and closure both equal its own truth region, so

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its boundary is empty.

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The Boolean event stayed fixed while its observational boundary changed.

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A point is on the boundary exactly when its smallest neighborhood meets

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both the event and its complement.

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The two witnesses lie in that same neighborhood: one inside the event

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and one outside.

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Neither witness has to be the centre.

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That neighborhood cannot certify either alternative completely.

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Symmetric difference compares two truth sets and removes their overlap.

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Boundary compares an event with the topology of available neighborhoods.

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Even a nonempty XOR region has empty boundary when the topology is

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discrete, so the two operations cannot be identified.

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When we replace positive X and Y by both signs, which changes:

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the XOR truth region, its interior, its closure, or its boundary?

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State the old and new boundary.

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The XOR truth region stays A and C.

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Its interior becomes A and C, its closure becomes A and C,

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and its boundary becomes empty.

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The earlier boundary was A, C and D.

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The interface changed, not classical evaluation.

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A boundary statement must identify its event, carrier and topology.

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Without those labels, a viewer may mistake Boolean disagreement for observational uncertainty

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or infer a physical edge that has no mathematical role in this

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finite example.
