WEBVTT

00:00:00.250 --> 00:00:05.046
A complete valuation answers every variable question in our chosen language.

00:00:05.057 --> 00:00:09.410
In the card example, X means dot and Y means stripe.

00:00:09.491 --> 00:00:13.411
Where a state has a two-bit annotation, those bits give its

00:00:13.465 --> 00:00:18.388
fixed X,Y values: one for true, zero for false.

00:00:18.908 --> 00:00:22.869
A selected formula list will have its own ordered headers.

00:00:24.008 --> 00:00:27.258
A makes X true and Y false.

00:00:27.733 --> 00:00:33.197
That state remains A whether we observe many formulas or only one.

00:00:34.096 --> 00:00:38.783
Now choose the ordered list X, Y as our observations.

00:00:39.412 --> 00:00:41.091
We call the list Phi.

00:00:41.575 --> 00:00:46.414
Ordered means that each position has a fixed meaning: position one is

00:00:46.468 --> 00:00:49.058
X, and position two is Y.

00:00:49.992 --> 00:00:52.477
An index is just a position label.

00:00:52.913 --> 00:00:57.449
We can write formula one and formula two to name those entries.

00:00:58.068 --> 00:01:03.158
An indexed family can include repetitions, so it is more informative than

00:01:03.158 --> 00:01:05.588
an ordinary set of formula names.

00:01:06.732 --> 00:01:08.820
A state supplies the input.

00:01:09.352 --> 00:01:13.433
The formula list specifies what to evaluate there.

00:01:13.944 --> 00:01:16.853
Neither is the resulting list of answers.

00:01:17.982 --> 00:01:20.112
Evaluate the list at A.

00:01:20.720 --> 00:01:24.081
X is true, so the first entry is one.

00:01:24.588 --> 00:01:28.296
Y is false, so the second entry is zero.

00:01:28.835 --> 00:01:32.551
The signature of A for this list is one, zero.

00:01:33.524 --> 00:01:35.927
At B both entries are one.

00:01:36.370 --> 00:01:38.551
At C they are zero, one.

00:01:38.987 --> 00:01:41.424
At D they are zero, zero.

00:01:41.891 --> 00:01:45.716
The formula headers tell us how to read every vector.

00:01:46.550 --> 00:01:51.184
A signature is the complete truth vector of the selected tuple at

00:01:51.205 --> 00:01:52.432
one valuation.

00:01:53.052 --> 00:01:58.328
It may have fewer entries than the valuation, or more, because we

00:01:58.339 --> 00:02:02.321
choose the formulas independently of the variable list.

00:02:03.435 --> 00:02:07.494
The zero at A says that Y is false at A.

00:02:08.057 --> 00:02:11.399
It does not mean that a reply has not arrived.

00:02:12.009 --> 00:02:17.311
Every entry of this semantic profile already has a definite value.

00:02:18.079 --> 00:02:23.895
The observation interface answers a different question: which affirmative events are available

00:02:23.895 --> 00:02:25.056
as certificates?

00:02:25.676 --> 00:02:30.580
With X and Y selected, an X certificate establishes X, and a

00:02:30.635 --> 00:02:33.204
Y certificate establishes Y.

00:02:34.067 --> 00:02:38.720
Absence of a Y certificate does not itself establish not Y.

00:02:39.192 --> 00:02:43.867
The topology gives no waiting time or certificate-delivery rule that would

00:02:43.867 --> 00:02:45.588
license that conclusion.

00:02:46.487 --> 00:02:51.239
Knowing the complete semantic profile would tell us that Y is false

00:02:51.239 --> 00:02:51.807
at A.

00:02:52.311 --> 00:02:55.794
Having no Y certificate is a different situation.

00:02:56.413 --> 00:03:01.763
Keep the instructor's mathematical table separate from the evidence actually supplied

00:03:01.763 --> 00:03:02.793
to an observer.

00:03:03.815 --> 00:03:09.053
A viewer says, “The second bit is zero because no stripe certificate

00:03:09.053 --> 00:03:09.731
arrived.”

00:03:10.276 --> 00:03:14.747
Does that correctly explain the zero in A's complete signature?

00:03:26.964 --> 00:03:27.380
No.

00:03:27.880 --> 00:03:30.928
The bit is zero because Y is false at A.

00:03:31.508 --> 00:03:36.261
Missing delivery is not what the signature records, and our topology does

00:03:36.282 --> 00:03:37.941
not model delivery.

00:03:38.804 --> 00:03:43.241
Choose a different list: the single conjunction formula X and Y.

00:03:43.690 --> 00:03:45.653
There is just one coordinate.

00:03:45.951 --> 00:03:50.248
B has signature one, while A, C and D all have signature

00:03:50.258 --> 00:03:53.823
zero, because each makes that conjunction false.

00:03:54.640 --> 00:03:57.721
Those three states remain different valuations.

00:03:58.370 --> 00:04:01.551
This observation simply does not distinguish them.

00:04:02.129 --> 00:04:05.731
A zero signature is not an extra state and is not an

00:04:05.785 --> 00:04:07.650
unknown truth value.

00:04:08.448 --> 00:04:12.331
If the list is only X instead, A and B both give

00:04:12.342 --> 00:04:14.985
one, while C and D both give zero.

00:04:15.548 --> 00:04:19.748
The same carrier now has a different grouping of equal signatures.

00:04:20.898 --> 00:04:24.174
Selecting a test changes the presentation.

00:04:24.645 --> 00:04:29.203
It does not remove any possible valuation or assert that the selected

00:04:29.213 --> 00:04:30.564
formula is true.

00:04:31.039 --> 00:04:35.186
Learning a premise is a separate operation later in the course.

00:04:36.057 --> 00:04:40.290
We can also describe a signature by listing the positions where its

00:04:40.300 --> 00:04:41.708
entries are one.

00:04:42.169 --> 00:04:45.313
This set of indices is called its support.

00:04:45.799 --> 00:04:50.779
An index names a position, not merely a formula: two positions can

00:04:50.789 --> 00:04:54.554
carry the same formula and still be two separate members of the

00:04:54.554 --> 00:04:55.313
support.

00:04:56.213 --> 00:05:00.130
For the list X, Y, A's support is the singleton containing

00:05:00.140 --> 00:05:01.174
index one.

00:05:01.630 --> 00:05:05.178
B's support contains indices one and two.

00:05:05.801 --> 00:05:08.437
C's support contains index two.

00:05:09.117 --> 00:05:14.421
D's support is empty, because neither selected formula is true there.

00:05:15.266 --> 00:05:20.131
An empty support is still the profile of a perfectly definite state.

00:05:20.574 --> 00:05:23.156
D has not disappeared from the carrier.

00:05:24.266 --> 00:05:26.731
Order matters when reading the vector.

00:05:27.217 --> 00:05:32.325
If we list Y before X, A's vector becomes zero, one.

00:05:32.724 --> 00:05:36.503
The state did not change; the coordinate meanings did.

00:05:37.022 --> 00:05:41.569
Never compare bit strings after silently changing their headers.

00:05:42.708 --> 00:05:46.956
A selected observation may itself contain NOT.

00:05:47.472 --> 00:05:50.310
Consider the tuple X, not X.

00:05:51.029 --> 00:05:54.025
Four two-bit patterns can be written down.

00:05:54.629 --> 00:05:57.776
Which of them can actually occur at a valuation?

00:06:14.025 --> 00:06:17.254
Only one, zero and zero, one.

00:06:17.720 --> 00:06:21.645
A and B make X true and not X false.

00:06:22.170 --> 00:06:25.941
C and D make X false and not X true.

00:06:26.796 --> 00:06:31.592
Zero, zero is impossible because one of a statement and its negation

00:06:31.689 --> 00:06:33.918
must be true in classical logic.

00:06:34.471 --> 00:06:38.446
One, one is impossible because they cannot both be true.

00:06:38.988 --> 00:06:43.860
Written bit patterns need not all be realized by the selected formulas.

00:06:44.969 --> 00:06:49.917
A certificate for not X is affirmative evidence of that selected formula. “

00:06:50.420 --> 00:06:56.137
Positive observation” means affirming an available formula, not banning negation from its

00:06:56.137 --> 00:06:56.854
syntax.

00:06:57.979 --> 00:07:01.307
An indexed list may repeat a formula.

00:07:01.389 --> 00:07:05.138
For X, X, Y, A has signature one, one, zero.

00:07:05.635 --> 00:07:10.536
Its support contains indices one and two, even though those positions carry

00:07:10.536 --> 00:07:11.856
the same formula.

00:07:12.716 --> 00:07:16.986
The repeated X contributes the same truth region twice.

00:07:17.483 --> 00:07:22.908
The topology generated from these regions is therefore unchanged from the list

00:07:23.006 --> 00:07:27.397
X, Y: no new generating subset was added.

00:07:28.196 --> 00:07:32.341
But the presentation still remembers two separate coordinates.

00:07:32.991 --> 00:07:38.403
Later, a distance can count contributions coordinate by coordinate.

00:07:38.910 --> 00:07:43.834
Topology alone does not retain all of that presentation data.

00:07:44.806 --> 00:07:46.554
Use two observations.

00:07:47.190 --> 00:07:48.930
Observation one is Y.

00:07:49.461 --> 00:07:53.417
Observation two is the conjunction X and Y.

00:07:53.968 --> 00:07:58.014
At C, write the two-entry signature and its support.

00:07:58.600 --> 00:08:00.565
Then find D’s signature.

00:08:01.067 --> 00:08:05.071
Does this two-observation tuple distinguish A from D?

00:08:25.646 --> 00:08:29.511
At C, Y is true but X and Y is false.

00:08:29.946 --> 00:08:35.727
The signature is one, zero and its support contains only index one.

00:08:36.137 --> 00:08:41.045
At D both formulas are false, so the signature is zero, zero.

00:08:42.001 --> 00:08:47.242
A also gives zero, zero: Y is false and the conjunction is

00:08:47.274 --> 00:08:47.879
false.

00:08:48.362 --> 00:08:53.815
This tuple cannot distinguish A from D, despite their different X values.

00:08:54.890 --> 00:09:00.609
A valuation, a selected formula tuple and its complete signature are three

00:09:00.609 --> 00:09:01.824
different objects.

00:09:02.479 --> 00:09:08.240
Equal signatures identify the distinctions the chosen observations cannot make.

00:09:08.820 --> 00:09:13.866
Next we will use their truth regions to construct the observation space

00:09:13.866 --> 00:09:15.009
explicitly.
